Question

In the steady state of circuit, ratio of energy stored in capacitor to the energy stored in inductor is Here L = 0.2 mH and C = 500 $\mu F$

Answer 1

$4=i\times (1+3)\Rightarrow i=1A$

$U_L=\frac{1}{2}L{i}^2=\frac{1}{2}\times 2\times {10}^{-4}\times 1^2$

$U_C=\frac{1}{2}C{V}^2=\frac{1}{2}\times 500\times {10}^{-6}\times 1^2$

$\frac{U_C}{U_L}=\frac{5}{2}=2.50$