Question

In the sulphar estimation, $0.157$ g of an organic compound gave $0.4813$ g of barium sulphate. What is the percentage of Sulphur in the compound?

• A. $42.10$%
• B. $36.45$%
• C. $51.95$%
• D. $48.33$%

Answer 1

The correct option is A $42.10$%

Mass of organic compound $=0.157g$

Mass of $BaS{O}_4=0.4813g$

Percentage of Sulphur $=\frac{32}{233}\times \frac{MassofBaS{O}_4}{Massoforganiccompound}\times 100$

% $S=\frac{32}{233}\times \frac{0.4813}{0.157}\times 100=42.10$%