In the triangle above, which of the following must be true?

p = r

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p < r

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p > r

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p = 4

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p > 4

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Solution

The correct option is B $p > r$
Given, $∠$ $M = 80$ and $∠$ $Q = 30$
We have, $∠ M + ∠ N + ∠ Q = 180^{o}$
$∴ N = 180 - 80 - 30 = 70$
Since angle $M$ is greater than angle $N$ , length of side $N Q$ must be greater than $M Q$ .
Therefore, $4 + p > 4 + r$ , which implies $p > r$ .

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In the triangle above, which of the following must be true?

The correct option is B p>rGiven, ∠ M=80 and ∠ Q=30We have, ∠M+∠N+∠Q=180o∴N=180−80−30=70Since angle M is greater than angle N, length of side NQ must be greater than MQ.Therefore, 4+p>4+r, which implies p>r.

The correct option is B $p > r$
Given, $∠$ $M = 80$ and $∠$ $Q = 30$
We have, $∠ M + ∠ N + ∠ Q = 180^{o}$
$∴ N = 180 - 80 - 30 = 70$
Since angle $M$ is greater than angle $N$ , length of side $N Q$ must be greater than $M Q$ .
Therefore, $4 + p > 4 + r$ , which implies $p > r$ .