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Question

In the triangular solid shown in figure, points A and B are vertices. The triangular faces are isosceles. The solid has a height of 12, a length of 21, and a width of 18. Calculate the distance between A and B.
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A
95
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B
358
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C
374
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D
385
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E
611
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Solution

The correct option is C 374
Given that the height is 12 and width is 21.
The altitude from A on base will cut the base into two equal halfs because the triangle is isosceles.
Therefore the length of an equal side of isosceles triangle is 122+92=144+81=225=15
Now the distance from A to B is 152+212=225+441=666=374

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