Question

In the uniform electric field shown in figure, $V_A-V_C$ is :

• A. 10 V
• B. 20 V
• C. 40 V
• D. 5 V

Answer 1

The correct option is B 20 V

$|V_A-V_C|=E\times 1=20V$
As $\overrightarrow{E}$ is directed from point A to B, point A is at a higher potential than point C.
planes perpendicular to an uniform electric field are equipotential planes. As B and C lie on the same plane perpendicular to $\overrightarrow{E}$ , they are at same potential.
As A and D lie on the same plane perpendicular to $\overrightarrow{E}$ , they are at same potential.