In the uniform electric field shown in figure, $V_{D} - V_{B}$ (in volts) is :

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Solution

The correct option is A 20
$| V_{B} - V_{D} | = E \times 1 = 20 V$
As $\to E$ is directed from point A to B, point A is at a higher potential than point B.
planes perpendicular to an uniform electric field are equipotential planes. As B and C lie on the same plane perpendicular to $\to E$ , they are at same potential.
As A and D lie on the same plane perpendicular to $\to E$ , they are at same potential.
$V_{D} - V_{B} = + 20 V$

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