In the velocity-time graph, the distance travelled by the particle between 1.0 sec and 4.0 sec, is approximately
A
50m
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B
40m
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C
30m
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D
20m
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Solution
The correct option is A40m In a velocity time graph , the area of the graph gives the total displacement of the graph Area of the graph = Area of the rectangle + Area of the triangle =3×11.25+12×3×(15−11.25) =39.375 ≈40m