Question

In this equilibrium reaction: $A+B\rightleftharpoons AB+heat$, in a closed container, how could the forward reaction rate be increased?

• A. Increasing $\left[AB\right]$
• B. Increasing $\left[A\right]$
• C. Removing some of $AB$
• D. Removing some of $\left[A\right],\left[B\right]$
• E. All of the above

Answer 1

Answer: (B), (C)

Increasing $\left[A\right]$
Removing some of $AB$

The given equilibrium reaction is :-

$A+B\rightleftharpoons AB+heat$

$\left(I\right)$ if $\left[A\right]$ is increased; to compensate this increase, by Le Chartelier's principle, the reaction proceeds towards formation of products.

$\left(II\right)$ on removing $\left[AB\right]$, then the reaction will proceed in product formation direction to compensate the decrease as suggested by Le Chaltelier's principle.