In this sequence, incorrect statement is

'A' is phthalimide

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C is methyl phathalimide

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Formation of 'D' and 'E' from 'A' is Hoffmann bromamide reaction

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Among the final products one of the product is 1⁰amine

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Solution

The correct option is C Formation of 'D' and 'E' from 'A' is Hoffmann bromamide reaction
A = Phthalimide; B= potassium salt of A ; C = N - methyl phthalimide D & E = Pot. Phthalate and methyl amine

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Similar questions

C H C l_{3}

N a O H

1^{o}

N -

We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

Benzoic acid (A) N H_{3} - -- \to Δ P B r_{2} - --- \to N a O H Q

A N_{3} H - --- \to H_{2} S O_{4} R i . H N O_{2} - ----- \to i i . H_{2} O, Δ S

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