In triangle ABC - 1-tan B -2-tan C -2 is equal toA- None of theseB- 2 a-a-b-cC- 2 b-a-b-cD- 2 c-a-b-c

The correct option is B 1 tanB 2.tanC 2 =1 √((s a)(s c)(s a)(s b)/s^2(s b)(s c)) =1 s a/s=a s=2a/a+b+c ...

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Trigonometric Ratios of Multiples of an Angle

In triangle A...

Question

In triangle ABC, $1 - t a n \frac{B}{2} . t a n \frac{C}{2}$ is equal to

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None of these

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A + B + C = 180^{\circ},

\frac{t a n A + t a n B + t a n C}{t a n A t a n B t a n C}

△ A B C, (a + b + c) (t a n \frac{A}{2} + t a n \frac{B}{2})

△ A B C

∣ ∣ ∣ ∣ ∣ \begin{matrix} cot \frac{A}{2} & cot \frac{B}{2} & cot \frac{C}{2} tan \frac{B}{2} + tan \frac{C}{2} & tan \frac{A}{2} + tan \frac{C}{2} & tan \frac{A}{2} + tan \frac{B}{2} 1 & 1 & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

A B C

cot \frac{A}{2} cot \frac{B}{2} = c, cot \frac{B}{2} cot \frac{C}{2} = a and cot \frac{C}{2} cot \frac{A}{2} = b

\frac{1}{s - a} + \frac{1}{s - b} + \frac{1}{s - c} =

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