Question

In triangle ABC, AB = AC; BE $\perp$ AC and CF $\perp$ AB.Is BE = CF?

• A. True
• B. False

Answer 1

The correct option is A True

In $△BFC$ and $△BEC$,
$BC=BC$ (Common)
$\angle FCB=\angle EBC$ (Given, AB = AC)
$\angle BFC=\angle BEC$ (each ${90}^{\circ }$)
Thus, $△BFC\cong △CEB$ (ASA rule)
Hence, $BE=CF$ (By cpct)