In $△ A B C$ , ${A C}^{2} = {A B}^{2} + {B C}^{2}$ , then right angle is at ___________.

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Solution

When $A B^{2} + B C^{2} = A C^{2}$ $\Rightarrow$ Right angle is at vertex $B .$
$∠ A B C = 90^{\circ}$

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Similar questions

In a right angled $△$ ABC, right angled at B, which of the following is true?

△ A B C

B

{A B}^{2} + {B C}^{2} = A C^{2}

B C^{2}

A B^{2}

A C^{2}

Δ

A B^{2} = B C^{2} + A C^{2},

Δ

A B^{2} + B C^{2} + A C^{2}

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