Question

In $△ABCand△DEF$, $AB=FD$ and $\angle A=\angle D$. The two triangles will be congruent by SAS axiom if

• A. $BC=EF$
• B. $AC=DE$
• C. $AC=EF$
• D. $BC=DE$

Answer 1

The correct option is B $AC=DE$


In above triangles, $△ABCandDEF$
$AB=FD$
$\angle A=\angle D$
Now, for $△ABCand△DEF$ to be congruent by SAS axiom, $AC$ must equals $DE$
i.e $AC=DE$ is the correct option.