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Question

IN $$\triangle \ ABC$$ right angled at $$C$$, find the value of $$\cos (A+B)$$.
1785483_7cc576a3c76947f0ad1fd12c9b06b8b3.png


Solution

In Fig.
$$ \because \angle C=90^o$$
$$\therefore \angle A+ \angle B =90^o$$           (By angle sum property)
Hence, $$\cos (A+B)= \cos (90^o)= 0$$

Mathematics

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