Question

In $△PQR,\angle Q={40}^o,\angle R={75}^o$, then find the shortest and the longest side of the triangle

Answer 1

$⟶\angle Q={40}^o$

$\angle R={75}^o$

$\therefore \angle P={180}^o-({40}^o+{75}^o)$

$\therefore \angle P=180-115$

$\therefore \angle P={65}^o$

Side opposite to greatest angle is greatest and side opposite to shortest angle is shortest.

$\therefore$ side $PR$ is shortest

$\therefore$ side $PQ$ is longest