Question

In two concentric circles with centre O, if AD is the chord of the larger circle, then AB = CD.

• A. True
• B. False

Answer 1

The correct option is A

True

Draw OM ⊥ AD.
OM bisects AD as OM ⊥ AD.
($\because$ perpendicular from the centre of a circle to its chord bisects the chord)
⇒ AM = MD --- (i)
OM bisects BC as OM ⊥ BC.
($\because$ perpendicular from the centre of a circle to its chord bisects the chord)
⇒ BM = MC --- (ii)
From (i) and (ii),
AM - BM = MD - MC
⇒ AB = CD