Question

In vapour state, sulphur $\left(S_2\right)$ shows paramagnetic behaviour due to:

• A. presence of one unpaired electron in the antibonding $\sigma$ orbitals
• B. presence of two unpaired electrons in the bonding $\pi$ orbitals
• C. presence of one unpaired electron in the antibonding $\pi$ orbitals
• D. presence of two unpaired electrons in the antibonding $\pi$ orbitals

Answer 1

The correct option is D presence of two unpaired electrons in the antibonding $\pi$ orbitals

$S_2$ has two unpaired electrons in its antibonding $\pi$ orbitals. Thus, the $S_2$ is paramagnetic.