Question

In water molecule, the two $O-H$ bonds are oriented at an angle of ${104.5}^o$. In $B{F}_3$, the three $B-F$ bonds are oriented at an angle of ${120}^o$. In $Be{F}_2$, the two $Be-F$ bonds are oriented at an angle of ${180}^o$. Which of the following will have highest dipole moment?

• A. $Be{F}_2$
• B. $B{F}_3$
• C. $H_{2}O$
• D. All have zero dipole moment.

Answer 1

Answer: (C)

$H_{2}O$

$B{F}_3$ and $Be{F}_2$ both have the symmetric structures, trigonal planner and linear respectively.

that's why $B{F}_3$ and $Be{F}_2$ have zero dipole moment.

$H_{2}O$ has $V$ shape that is the unsymmetrical structure that's why $H_2O has the maximum dipole moment.

So the correct option is $C$.