In what ratio a mixture of $30 %$ alcohol strength be mixed with that of $50 %$ alcohol strength so as to get a mixture of $45$ alcohol strength ?

1 : 2

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1 : 3

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2 : 1

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3 : 1

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Solution

The correct option is B $1 : 3$
Let the ratio be 1:x
Then according to the question
$\Rightarrow 30 \times 1 + 50 x = (1 + x) 45$
$\Rightarrow 30 + 50 x = 45 + 45 x$
$\Rightarrow 50 x - 45 x = 45 - 30$
$\Rightarrow 5 x = 15$
$\Rightarrow x = 3$
$∴$ ratio is $1 : 3$

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In what ratio a mixture of 30% alcohol strength be mixed with that of 50% alcohol strength so as to get a mixture of 45 alcohol strength ?

The correct option is B 1:3Let the ratio be 1:xThen according to the question⇒30×1+50x=(1+x)45⇒30+50x=45+45x⇒50x−45x=45−30⇒5x=15⇒x=3∴ ratio is 1:3

In what ratio a mixture of $30 %$ alcohol strength be mixed with that of $50 %$ alcohol strength so as to get a mixture of $45$ alcohol strength ?

The correct option is B $1 : 3$
Let the ratio be 1:x
Then according to the question
$\Rightarrow 30 \times 1 + 50 x = (1 + x) 45$
$\Rightarrow 30 + 50 x = 45 + 45 x$
$\Rightarrow 50 x - 45 x = 45 - 30$
$\Rightarrow 5 x = 15$
$\Rightarrow x = 3$
$∴$ ratio is $1 : 3$