In what time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

$\frac{1}{10} s$

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$10 s$

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$110 s$

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$\frac{1}{110} s$

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Solution

The correct option is A
$\frac{1}{10} s$

As we know, current is the rate of flow of charge.
Charge q = 10 coulomb
Given:
Time = t
Current I = 100 amperes
Formula for current due to charge flowing i.e., I = $\frac{q}{t}$
Time, t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s

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Q. In how much time should an electric charge of 10 C flow between two terminals in a circuit to maintain a constant electric current of

100

A ?

(A)

\frac{1}{10} s

(B)

10 s

(C)

110 s

(D)

\frac{1}{110} s

[1 Mark]

In how much time (in seconds) should a charge of $10$ coulombs flow between two terminals of a circuit so as to maintain a constant current of $100 A ?$

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In what time (in seconds) should a charge of 10 C flow between the two terminals so as to maintain a constant current of 100 A?

The correct option is A 110 s As we know, current is the rate of flow of charge. Charge q = 10 coulomb Given: Time = t Current I = 100 amperes Formula for current due to charge flowing i.e., I = qt Time, t = qI = 10100 = 110 s

The correct option is A
$\frac{1}{10} s$

As we know, current is the rate of flow of charge.
Charge q = 10 coulomb
Given:
Time = t
Current I = 100 amperes
Formula for current due to charge flowing i.e., I = $\frac{q}{t}$
Time, t = $\frac{q}{I}$ = $\frac{10}{100}$ = $\frac{1}{10}$ s