In which case compounds of Cr show minimum radius.

K_{2} C r O_{7}

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C r O_{2} C l_{2}

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C r_{2} (S O_{4})_{3}

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C r C l_{2}

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Solution

The correct options are
A $K_{2} C r O_{7}$
B $C r O_{2} C l_{2}$

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