In which $(C - C)$ bond of $(H_{3} 3 C - 2 C H_{2} - 1 C H_{2} - B r)$ , the inductive effect is expected to be the least?

C - 3

and

C - 2

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C - 1

and

H

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C - 2

and

H

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C - 3

and

H

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Solution

The correct option is D $C - 3$ and $H$ .
The magnitude of the inductive effect decreases as the number of intervening bonds increases. Hence, the inductive effect is least in the bond between $C_{3}$ and $H$ as this hydrogen atom is farthest from $B r$ atom.

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Similar questions

In the compound $^{1} C H_{2}$ = $^{2} C - H |^{3} C | H -^{4} H | C | H -^{5} C$ ≡ $^{6} C H$ , the hybridization of $C_{3}$ is:

S_{N} 1

{C H}_{3} - C H_{2} - B r

\begin{matrix} C H_{3} | C H_{3} & - & C & - & C H_{3} | B r \end{matrix}

O_{2} N C H_{2} C H_{2} O^{-}

C H_{3} C H_{2} O^{-}

H_{3} C - H, H_{3} C - B r

H_{3} C - N H_{2}, H_{3} C - O H

H_{3} C - O H, H_{3} C - S H

B e - C H_{2} - C H_{2} - B r \to H - C \equiv C - H

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