In which of the following cases, the carbocation (I) is less stable than the carbocation (II) ?
A
C6H5+CH2(I),CH2=CH2+CH2(II)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
H3C+CH2(I),CH2−⨁CH2(II)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
CH2+CH(I),CH3−+CH2(II)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CCH2+CH(I),CH3−+CH2(II) In A, I is more stable due more resonance structures of benzene. In B, I is more stable due to complete octet. In C, II is more stable due to complete octet.