In which of the following compound $M n$ shows minimum radius?

M n O_{2}

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K M n O_{4}

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M n O

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None of these

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Solution

The correct option is D $K M n O_{4}$
As oxidation state of central metal ion increases, the electron to proton ratio decreases and therefore, size of ion decreases. In $K M n O_{4}$ , $M n$ is in +7 oxidation sate. So, due to maximum +ve charge radius will be lowest.

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