The correct option is C C2H4
Alkanes have sp3 hybridised carbon, as all s and p orbitals take part in bond formation.
Alkenes have sp2 hybridised carbon having double bond, as one s and only two p orbitals take part in bond formation. While one p-orbital is empty.
Alkynes have sp hybridised carbon having triple bond, as one s and only one p orbital take part in bond formation. While two p-orbital is empty. Hence, option C is correct.