In which of the following compounds, sulphur show maximum oxidation number?

S O_{3}

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H_{2} S_{2} O_{7}

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All have same oxidation number for sulphur

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H_{2} S O_{4}

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Solution

The correct option is C All have same oxidation number for sulphur
(i) Oxidation number of S in $H_{2} S O_{4}$ :
$+ 2 + x - 8 = 0 x = + 6$

(ii) Oxidation number of S in $S O_{3}$ :
$x - 6 = 0 x = + 6$

(iii) Oxidation number of S in $H_{2} S_{2} O_{7}$ :
$2 + 2 x - 14 = 0 2 x = + 12 x = + 6$

Hence, option (d) is correct.

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