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Valency and Oxidation State

In which of t...

Question

In which of the following does sulphur has the lowest oxidation state?

H_{2} {S O}_{4}

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S O_{3}

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H_{2} {S O}_{3}

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H_{2} S

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Solution

The correct option is D $H_{2} S$
Sulphur has the lowest oxidation state in $H_{2} S$ . The oxidation state of
$S$ in $H_{2} S$ is $- 2$ . The oxidation state of $S$ in $H_{2} S O_{4}$ , $S O_{2}$ and $H_{2} S O_{3}$ are $+ 6$ , $+ 4$ and $+ 4$ respectively.

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Similar questions

H_{2} {S O}_{4}

H_{3} {P O}_{4}, H_{2} {S O}_{4}, H_{3} {P O}_{3}, H_{2} {C O}_{3}, H_{2} S_{2} O_{7}, H_{3} B O_{3}, H_{3} {P O}_{2}, H_{2} {C r O}_{4}, H_{2} {S O}_{3}

S + O_{2} \to {S O}_{2}; Δ H = - 298.2 k J

{S O}_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

{S O}_{3} + H_{2} O \to H_{2} {S O}_{4}; Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

H_{2} {S O}_{4}

K_{2} {C r}_{2} O_{7} + K I + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {C r}_{2} {({S O}_{4})}_{3} + I_{2} + H_{2} O

K M n O_{4} + {N a}_{2} {S O}_{3} \to M n O_{2} + {N a}_{2} {S O}_{4} + K O H

C u + H {N O}_{3} \to C u {({N O}_{3})}_{2} + {N O}_{2} + H_{2} O

K M {n O}_{4} + H_{2} C_{2} O_{4} + H_{2} {S O}_{4} \to K_{2} {S O}_{4} + {M n S O}_{4} + {C O}_{2} + H_{2} O

H_{2} {S O}_{4}

H_{2} {S O}_{4}

{S O}_{2}

{S O}_{3}

{S O}_{3}

H_{2} {S O}_{4}

H_{2} {S O}_{4}

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