In which of the following does the reaction go almost to completion ?

K = 10^{6}

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K = 10^{3}

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K = 10^{- 6}

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K = 10^{- 12}

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Solution

The correct option is A $K = 10^{6}$
For the reaction in option A, the value of the equilibrium constant $K = 10^{6}$ . It is very high. It means products are pesent in large excess as compared to reactants. Hence, the reaction almost goes to completion.

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In which of the following does the reaction go almost to completion ?

The correct option is A K=106For the reaction in option A, the value of the equilibrium constant K=106 . It is very high. It means products are pesent in large excess as compared to reactants. Hence, the reaction almost goes to completion.

The correct option is A $K = 10^{6}$
For the reaction in option A, the value of the equilibrium constant $K = 10^{6}$ . It is very high. It means products are pesent in large excess as compared to reactants. Hence, the reaction almost goes to completion.