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Calorimetry

In which of t...

Question

In which of the following equilibrium, $K_{p}$ is less than $K_{c}$ ?

N_{2} O_{4} \Leftrightarrow 2 N O_{2}

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2 H I \Leftrightarrow H_{2} + I_{2}

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2 S O_{2} + O_{2} \Leftrightarrow 2 S O_{3}

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N_{2} + O_{2} \Leftrightarrow 2 N O

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Solution

The correct option is C $2 S O_{2} + O_{2} \Leftrightarrow 2 S O_{3}$
The relationship between $K_{p}$ and $K_{c}$ is $K_{p} = K_{c} (R T)^{Δ n}$ .

When the value of $Δ n$ is negative, the term $(R T)^{Δ n}$ becomes less than 1.

In such cases, $K_{p}$ becomes less than $K_{c}$ .

This is true for the reaction $2 S O_{2} + O_{2} \Leftrightarrow 2 S O_{3}$ as $Δ n = 2 - 3 = - 1$ .

Where, $Δ n$ = number of moles of product- number of moles of reactant

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Similar questions

298 K

\frac{k_{p}}{k_{c}}

N_{2} O_{4} ⇌ 2 N O_{2}

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

X + Y ⇌ 4 Z

A + 3 B ⇌ 7 C

\frac{K_{P}}{K_{C}}

N_{2} O_{4} ⇌ 2 {N O}_{2}

2 S O_{2} + O_{2} ⇌ 2 {S O}_{3}

X + Y ⇌ 4 Z

A + 3 B ⇌ 7 C

2 N O + O_{2} ⇌ 2 N O_{2}

K_{C_{1}}

N O_{2} + S O_{2} ⇌ S O_{3} + N O

K_{C_{2}}

2 S O_{3} ⇌ 2 s O_{2} + O_{2}

K_{C_{3}}

In which of the following equilibria, the value of $K_{P}$ is less than $K_{C}$

K

K_{1}

K_{2}

N_{2} + 2 O_{2} ⇋ 2 N O_{2}, K

N_{2} + O_{2} ⇋ 2 N O, K_{1}

2 N O + O_{2} ⇋ 2 N O_{2}, K_{2}

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