In which of the following has the average oxidation number of oxygen been arranged in increasing order ?

B a O_{2} < K O_{2} < O_{3} < O F_{2}

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O F_{2} < K O_{2} < B a O_{2} < O_{3}

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B a O_{2} < O_{3} < O F_{2} < K O_{2}

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K O_{2} < O F_{2} < O_{3} < B a O_{2}

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Solution

The correct option is A $B a O_{2} < K O_{2} < O_{3} < O F_{2}$
Oxidation number of oxygen in :
$B a O_{2} = - 1$
$K O_{2} = - \frac{1}{2} O_{3} = 0 O F_{2} = + 2$
Hence, the order of increasing oxidation number of oxygen in the given compounds is : $B a O_{2} < K O_{2} < O_{3} < O F_{2}$

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In which of the following has the oxidation number of oxygen been arranged in increasing order?

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