Question

In which of the following has the oxidation number of oxygen been arranged in increasing order?

• A. BaO₂< KO₂< O₃< OF₂
• B. OF₂< KO₂< BaO₂< O₃
• C. BaO₂< O₃< OF₂< KO₂
• D. KO₂< OF₂< O₃< BaO₂

Answer 1

The correct option is A

BaO₂< KO₂< O₃< OF₂

Compound NO of Oxygen

$Ba{O}_2$ -1

$K{O}_2$ $\frac{-1}{2}$

$O_3$ O

$O{F}_2$ +2

$O{F}_2$>$O_3$>$K{O}_2$>$Ba{o}_2$