In which of the following molecules $C$ atom assumes $s p$ and $s p^{3}$ hybrid states only?

C H_{2} - C H = C H_{2}

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C H_{2} = C H - C H = C H_{2}

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C H_{3} C H_{2} - C = C H

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C H_{2} = C H - C N

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Solution

The correct option is C $C H_{3} C H_{2} - C = C H$
$A)$ $s p^{3} C H_{3} - s p^{2} C H = s p^{2} C H_{2}$
$B)$ $s p^{2} C H_{2} = s p^{2} C H - s p^{2} C H = s p^{2} C H_{2}$
$C)$ $s p^{3} C H_{3} s p^{3} C H_{2} - s p C = s p C H$
$D)$ $s p^{2} C H_{2} = s p^{2} C H = s p C N$
Therefore, $C$ is the correct answer.

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