In which of the following, oxidation number of chlorine is $+ 5 ?$

C l_{2} O_{7}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C l O}_{3}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H O}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C l O}_{4}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B ${C l O}_{3}^{-}$
Oxidation number of $C l_{2} O_{7}$ :-
$2 x - 14 = 0$
$x = 7$
Oxidation number of ${C l O_{3}}^{-}$ :-
$x - 6 = - 1$
$x = 5$
Oxidation number of $C l O^{-}$ :-
$x - 2 = - 1$
$x = 1$
Oxidation number of ${C l O_{4}}^{-}$ :-
$x - 8 = - 1$
$x = 7$
hence option B is correct.

Suggest Corrections

Similar questions

C l O_{3}^{-}

C l_{2} O_{7}, C l_{2} O, H C l, C l F_{3}, C l_{2}

C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}

C l O_{4}^{-}

{N a}_{2} S_{2} O_{7}

{K I}_{3}

{C l O}_{3}^{-}

{C l O}_{4}^{-}

C l O_{4}^{-}

C l O_{4}^{-}

Join BYJU'S Learning Program