The correct option is
A H2+2,He2For H−2, 1s2∗1s1 Bond Order = 2−12=0.5
For He−22, 1s2∗1s22s2 Bond Order = 4−22=1
For He2, 1s2∗1s2 Bond Order = 2−22=0
For H+22, 1s0 Bond Order = 0−02=0
For H−2, 1s2∗1s1 Bond Order = 2−12=0.5
For He+22, 1s2 Bond Order = 2−02=1
For H+2, 1s1 Bond Order = 1−02=0.5
The bond order of H2+2 and He2 is zero, thus their existence is not possible.
Hence, option B is correct.