In which of the following process, the bond order increases and magnetic behaviour changes?

N_{2} ⟶ N_{2}^{+}

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C_{2} ⟶ C_{2}^{+}

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N O ⟶ N O^{+}

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O_{2} ⟶ O_{2}^{+}

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Solution

The correct option is D $N O ⟶ N O^{+}$
In $N O ⟶ N O^{+}$ the bond order increases and magnetic behaviour changes.
$N O$ has $15$ electrons, its bond order $= 1 / 2 [8 - 3] = 2.5$ and is paramagnetic; while $N O^{+}$ has $14$ electrons, , its bond order $= 1 / 2 [8 - 2] = 3$ is diamagnetic.

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Similar questions

$S_{1}$ : Bond order of $O_{2}^{-}$ is more than $O_{2}^{+}$
$S_{2}$ : $N O^{+}$ is more stable than $N_{2}^{+}$
$S_{3}$ : $C_{2}$ is more stable than $C_{2}^{+}$
State, in order, whether $S_{1}$ , $S_{2}$ , $S_{3}$ are true or false ?

Q. Which of the following molecules/species have identical bond order and same magnetic properties?

(I)

O_{2}

(II)

N O

(III)

N_{2}^{+}

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$ ?

(i). $N_{2} \to N_{2}^{+} + e^{-}$

(ii) $O_{2} \to O_{2}^{+} + e^{-}$

$N_{2}$ and $O_{2}$ are converted into monocations, $N_{2}^{+}$ and $O_{2}^{+}$ respectively. Which of the following is wrong ?

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In which of the following process, the bond order increases and magnetic behaviour changes?

The correct option is D NO⟶NO+In NO⟶NO+ the bond order increases and magnetic behaviour changes.NO has 15 electrons, its bond order =1/2[8−3]=2.5 and is paramagnetic; while NO+ has 14 electrons, , its bond order =1/2[8−2]=3 is diamagnetic.

The correct option is D $N O ⟶ N O^{+}$
In $N O ⟶ N O^{+}$ the bond order increases and magnetic behaviour changes.
$N O$ has $15$ electrons, its bond order $= 1 / 2 [8 - 3] = 2.5$ and is paramagnetic; while $N O^{+}$ has $14$ electrons, , its bond order $= 1 / 2 [8 - 2] = 3$ is diamagnetic.