Question

$S_1$ : Bond order of $O_2^{-}$ is more than $O_2^{+}$
$S_2$ : $N{O}^{+}$ is more stable than $N_2^{+}$
$S_3$ : $C_2$ is more stable than $C_2^{+}$
State, in order, whether $S_1$, $S_2$, $S_3$ are true or false ?

• A. FFT
• B. TTT
• C. TFT
• D. FTT

Answer 1

The correct option is D FTT

Bond order of $O_2^{-}$ = 1.5
Bond order of $O_2^{+}$ = 2.5
Bond order of $O_2^{-}$ is less than Bond order of $O_2^{+}$.
Hence, $S_2$ is false.

Bond order of $N{O}^{+}$ = 3
Bond order of $N_2^{+}$ = 2.5
Bond order $\alpha$ Stability of molecules/ions
So, $N{O}^{+}$ is more stable than $N_2^{+}$.
Hence, $S_3$ is true.

Bond order of $C_2$ = 2
Bond order of $C_2^{+}$ = 1.5
So, $C_2$ is more stable than $C_2^{+}$.
Hence, $S_4$ is true.
$\therefore$ the correct option is (d).