In which of the following reaction H2O2 acts as a reducing agent? (a) H2O2+2H++2e−→2H2O (b) H2O2−2e−→O2+2H+ (c) H2O2+2e−→2OH− (d) H2O2+2OH−−2e−→O2+2H2O.
A
(a), (c)
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B
(b), (d)
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C
(a), (b)
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D
(c), (d)
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Solution
The correct option is B (b), (d)
H2O2→O2+2H++2e−
and H2O2+2OH−→O2+2H2O+2e−
Oxidation state of O changes from −1 in H2O2 to 0 in O2
As it is getting oxidized , it acts reducing agent.