In which of the following reaction hydrogen peroxide is a reducing agent?

2FeCl₂+ 2HCl + H₂O₂→ 2FeCl₃ + 2H₂O

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Cl₂+ H₂O₂→ 2HCl + O₂

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HI+ H₂O₂→ 2H₂O + I₂

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H₂SO₃+ H₂O₂ → H₂SO₄+ H₂O

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Solution

The correct option is B
Cl₂+ H₂O₂→ 2HCl + O₂

$C l_{2} 0$ + $H_{2} O_{2}$ $\to$ $2 H C l - 1$ + $O_{2}$

In this reaction $H_{2} O_{2}$ works as reducing agent

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Similar questions

H_{2} O_{2}

2 F e C l_{2} + H_{2} O_{2} + 2 H C l \to 2 F e C l_{3} + 2 H_{2} O

H_{2} O_{2}

(a)

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

(b)

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

(c)

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

(d)

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

H_{2} O_{2}

H_{2} O_{2}

H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O

H_{2} O_{2} - 2 e^{-} \to O_{2} + 2 H^{+}

H_{2} O_{2} + 2 e^{-} \to 2 O H^{-}

H_{2} O_{2} + 2 O H^{-} - 2 e^{-} \to O_{2} + 2 H_{2} O

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