In which of the following reaction reactant and products are incorrectly matched?

F_{3} C - C H = C H_{2} + H C l \to F_{3} C - C l | C H - C H_{3}

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M e - C H = C H - O | | C - O C H_{3} + I C l \to M e - C l | C H - I | C H - O | | C - O C H_{3}

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P h - C H = C H - C H_{3} H B r - --- \to R O O R P h - C H_{2} - B r | C H - C H_{3}

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P h - C H = C H - C H = C H_{2} H C l - --- \to R O O R P h - C l | C H - C H = C H - C H_{3}

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Solution

The correct option is A $F_{3} C - C H = C H_{2} + H C l \to F_{3} C - C l | C H - C H_{3}$
A) $F_{3} C - C H = C H_{2} H^{+} - - \to F_{3} C - C H_{2} - \oplus C H_{2}$
$- C F_{3}$ being a strong electron withdrawing group will destabilise the secondary carbocation.

$F_{3} C - C H_{2} - \oplus C H_{2} C l^{-} - - \to F_{3} C - C H_{2} - C H_{2} C l$

B) Carbocation next to carbonyl group is unstable, hence $I^{+}$ attacks that carbon to avoid carbocation formation at that carbon.
C) HBr will show peroxide effect and benzyl free radical is more stable.
D)HCl will not show peroxide effect.

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