In which of the following reaction, the yield of the products does not increase by increase in the pressure?

N_{2} (g) + O_{2} (g) = 2 N O (g)

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2 S O_{2} (g) + O_{2} (g) = 2 S O_{3} (g)

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N_{2} (g) + 3 H_{2} (g) = 2 N H_{3} (g)

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P C l_{3} (g) + C l_{2} (g) = P C l_{5} (g)

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Solution

The correct option is B $N_{2} (g) + O_{2} (g) = 2 N O (g)$
In which $Δ n = 0$
$N_{2} (g) + O_{2} (g) = 2 N O (g)$
so here, K doesnt change with P.
i. $Δ n = 2 - (1 + 1) = 0$
ii. $Δ n = 2 - (2 + 1) = - 1$
iii. $Δ n = 2 - (1 + 3) = - 2$
iv. $Δ n = 1 - (1 + 1) = - 1$

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Similar questions

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

N_{2} (g) + O_{2} (g) ⇌ 2 N O (g)

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

2 H I_{(g)} ⟶ H_{2 (g)} + I_{2 (g)}

2 N H_{3 (g)} ⟶ N_{2 (g)} + 3 H_{2 (g)}

2 N O_{(g)} ⟶ N_{2 (g)} + O_{2 (g)}

P C l_{5 (g)} ⟶ P C l_{3 (g)} + C l_{2 (g)}

log \frac{K_{p}}{K_{c}} + log R T = 0

log \frac{K_{P}}{K_{C}} + log R T = 0

K_{p}

K_{c}

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