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Byju's Answer
Standard XII
Chemistry
Chiral Centres and Chirality
In which of t...
Question
In which of the following reactions, the product obtained is chiral?
A
C
H
3
C
O
C
H
3
N
a
B
H
4
−
−−−
→
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B
C
H
3
C
O
C
l
R
o
s
e
n
m
u
n
d
′
s
r
e
d
u
c
t
i
o
n
−
−−−−−−−−−−−−−
→
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C
C
H
3
C
H
2
C
O
2
C
H
2
C
H
3
S
n
,
H
C
l
−
−−−−
→
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D
C
H
3
C
H
2
C
O
C
H
3
L
i
A
l
H
4
−
−−−
→
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Solution
The correct option is
B
C
H
3
C
H
2
C
O
C
H
3
L
i
A
l
H
4
−
−−−
→
O
H
C
H
3
−
C
H
2
−
C
O
−
C
H
3
L
i
A
l
H
4
−
−−−
→
C
H
3
−
C
H
2
−
|
C
H
−
C
H
3
Product is
2
−
b
u
t
a
n
o
l
which is chiral.
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Similar questions
Q.
C
H
3
−
C
H
2
−
C
H
2
−
C
H
2
−
C
H
3
C
H
2
N
2
/
Δ
−
−−−−−
→
Products
Which of the following product(s) is/are can be obtained in the above reaction.
Q.
Match the column
A
,
B
and
C
suitably.
Reactabts
(
A
)
Products
(
B
)
Name of the reaction
(
C
)
C
H
3
−
C
H
3
+
C
l
2
C
O
2
+
H
2
O
Addition reaction
C
2
H
6
+
O
2
C
H
2
=
C
H
2
Thermal cracking
n
C
H
2
=
C
H
2
C
H
2
=
C
H
2
+
C
H
4
Substitution reactions
C
H
3
−
C
H
2
−
C
H
3
C
H
3
−
C
H
2
C
l
+
H
C
l
Polymerisation
C
H
≡
C
H
+
H
2
[
−
C
H
2
−
C
H
2
−
]
n
Combustion
Q.
Which of the following reaction is example of
S
N
2
reaction using
c
o
n
c
.
H
C
l
:
(
a
)
C
H
3
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
2
−
C
l
(
b
)
C
H
3
−
C
H
3
|
C
|
C
H
3
−
C
H
2
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
H
1
|
C
|
C
H
3
−
C
H
2
−
C
H
3
(
c
)
C
H
3
−
O
H
|
C
|
C
H
3
−
C
H
3
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
3
−
C
l
|
C
|
C
H
3
−
C
H
3
(
d
)
C
H
2
=
C
H
−
C
H
2
−
O
H
A
n
h
y
Z
n
C
l
2
/
△
−
−−−−−−−−
→
C
H
2
=
C
H
−
C
H
2
−
C
l
Q.
Rank the following in decreasing order of basic strength:
(i)
C
H
3
−
C
H
2
−
C
≡
C
−
(ii)
C
H
3
−
C
H
2
−
S
−
(iii)
C
H
3
−
C
H
2
−
C
O
2
−
(iv)
C
H
3
−
C
H
2
−
O
−
.
Q.
Identify the type of the following reaction of carbon compounds.
a. CH
3
-CH
2
-CH
2
-OH → CH
3
-CH
2
-COOH
b. CH
3
-CH
2
-CH
3
→ 3CO
2
+ 4H
2
O
c. CH
3
-CH = CH -CH
3
+ Br
2
→ CH
3
-CHBr - CHBr -CH
3
d. CH
3
-CH
3
+ Cl
2
→ CH
3
-CH
2
-Cl + HCl
e. CH
3
-CH
2
-CH
2
-CH
2
-OH → CH
3
-CH
2
-CH=CH
2
+ H
2
O
f. CH
3
-CH
2
-COOH + NaOH → CH
3
-CH
2
-COO - Na
+
+ H
2
O
g. CH
3
-COOH + CH
3
-OH → CH
3
-COO- CH
3
+ H
2
O
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