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Electronic Configuration and Oxidation States

In which pair...

Question

In which pair of compounds the oxidation state of nitrogen is -1?

a)ammonia ,hydroxylamine

b)nitric oxide and nitric acid

c)hydrazine and ammonia

d)hydrazine and hydroxylamine

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Solution

Oxidation state of N in

Ammonia, NH3 is -3

hydroxyl amine, NH2OH is -1

Nitric oxide is +2

Nitric acid HNO3 is +5

Hydrazine, NH2NH2 is -2

So, unfortunately , all options are incorrect.

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Similar questions

Q. One mole of hydrazine

(N_{2} H_{4})

10

moles of electrons in a reaction to form a new compound

X

. Assuming that all the nitrogen atoms in hydrazine appear in the new compound, what is the oxidation state of nitrogen in

X

? (Note There is no change in the oxidation state of hydrogen in the reaction)

2.5 m o l

(N_{2} H_{4})

25 m o l

of electrons on being converted to a new compound

X

. Assuming that there is no loss of nitrogen in the formation of the new compound and the oxidation state of

H^{+}

+ 1

throughout the reaction, then what is the oxidation number of nitrogen in compound

X

?

K_{2} C r_{2} O_{7}

react with hydrazine to form product. The oxidation state of

C r

in the product will be:

Q. Oxidation of a compound ‘X’ gives a product which reacts with phenyl hydrazine but does not give a sliver mirror test. The structure of ‘X’ is

Q. The mass of nitrogen per gram in hydrazine is exactly one and half the mass of nitrogen in the compound ammonia.

The fact illustrates the:

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