In which ratio of volume 0.4 M HCl and 0.9 M HCl are to be mixed such that the concentration of the resultant solution becomes 0.7 M ?

4:9

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2:3

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1:1

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6:1

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Solution

The correct option is B 2:3
Given: Molarity of the first solution=0.4 M
Molarity of the second solution = 0.9 M
Solution: Let the volume of 0.4 M HCl solution be $V_{1}$ and volume of solution 0.9 M HCl be $V_{2}$ .
According to the question,
$0.4 V_{1} + 0.9 V_{2} = 0.7 (V_{1} + V_{2})$ (1)
On simplifying we get,
$0.4 V_{1} - 0.7 V_{1} = 0.7 V_{2} - 0.9 V_{2}$
$- 0.3 V_{1} = - 0.2 V_{2}$
$\frac{V_{1}}{V_{2}} = \frac{2}{3}$
Hence, the correct option is (B).

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