In YDSE the first bright fringe after the centre fringe is observed at P. If the screen is continuously moved away from plane of slits, then ratio of intensity at point P to intensity at point O [center of screen]
A
remains same
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
keeps on increasing
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
can become ∞
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
first decreases and then increases
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D first decreases and then increases Path difference at P =ydD. As D increases, the path difference decreases. As the path length decreases from λ to λ/2, the intensity at P decreases from maximum to minimum. However, as the path length decreases from λ/2 to 0, the intensity at P increases from minimum to maximum again.