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Question

# In Young's double slit experiment, the wavelength of light used is doubled and the distance between the two slits is halved, the new fringe width becomes,

A
12 times
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B
2 times
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C
3 times
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D
4 times
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Solution

## The correct option is D 4 timesFringe width is given by, β=λDd Here, λ is the wavelength of light, D is the distance between the slit and the screen and d is the distance between the two slits. According to the given information, λ′=2λ, and d′=d2 ∴ β′=λ′Dd′=4λDd=4β So, the new fringe width becomes 4 times. Hence, (D) is the correct answer. Why this question:Concept: Fringe width is inversely proportional tothe distance between the slits(d),and directly proportional to wavelength λ.

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