CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In Young's double slit experiment, the wavelength of light used is doubled and the distance between the two slits is halved, the new fringe width becomes,

A
12 times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3 times
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4 times
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4 times
Fringe width is given by,
β=λDd

Here, λ is the wavelength of light, D is the distance between the slit and the screen and d is the distance between the two slits.

According to the given information,
λ=2λ, and d=d2
β=λDd=4λDd=4β
So, the new fringe width becomes 4 times.

Hence, (D) is the correct answer.

Why this question:Concept: Fringe width is inversely proportional tothe distance between the slits(d),and directly proportional to wavelength λ.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
YDSE Problems
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon