In Young's experiment ,light of wavelength $4000 A^{0}$ is used to produce bright fringes of width $0.6 m m$ , at a dipped in a liquid of refractive index $1.5$ , then the fringe width will be

0.2 m m

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0.3 m m

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0.4 m m

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1.2 m m

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Solution

The correct option is C $0.4 m m$
Fringe width, $β α λ$
$∴ \frac{β_{1}}{β_{2}} = \frac{λ_{1}}{λ_{2}}$
or $\frac{β_{1}}{β_{2}} = \frac{λ_{1}}{λ_{1} / μ}$
$∴ β_{2} = \frac{β_{1}}{β_{2}} = \frac{0.6}{1.5} = 0.4 m m$

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In Young's experiment ,light of wavelength 4000A0 is used to produce bright fringes of width 0.6mm , at a dipped in a liquid of refractive index 1.5 , then the fringe width will be

The correct option is C 0.4mmFringe width,βαλ∴β1β2=λ1λ2or β1β2=λ1λ1/μ∴β2=β1β2=0.61.5=0.4mm

In Young's experiment ,light of wavelength $4000 A^{0}$ is used to produce bright fringes of width $0.6 m m$ , at a dipped in a liquid of refractive index $1.5$ , then the fringe width will be

The correct option is C $0.4 m m$
Fringe width, $β α λ$
$∴ \frac{β_{1}}{β_{2}} = \frac{λ_{1}}{λ_{2}}$
or $\frac{β_{1}}{β_{2}} = \frac{λ_{1}}{λ_{1} / μ}$
$∴ β_{2} = \frac{β_{1}}{β_{2}} = \frac{0.6}{1.5} = 0.4 m m$