Question

Incentre of the triangle whose vertices are $(2,4)$ , $(6,4)$ and $(2,0)$ is:

• A. $(\frac{10}{3},\frac{8}{3})$
• B. $(6-2\sqrt{2},2\sqrt{2})$
• C. $(\frac{8}{3},\frac{10}{3})$
• D. $(2\sqrt{2},6-2\sqrt{2})$

Answer 1

Answer: (A)

$(\frac{10}{3},\frac{8}{3})$

Given vertices of triangle are $(2,4),(6,4)$ and $(2,0)$

Centroid of triangle =$(\frac{2+6+2}{3},\frac{4+4+0}{3})=(\frac{10}{3},\frac{8}{3})$