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Question

Increasing order of Δo of the following complex is:

A
[Cr(NH3)6]3+<[Cr(H2O)6]3+<[Cr(NO2)6]3
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B
[Cr(H2O)6]3+>[Cr(NH3)6]3+>[Cr(NO2)6]3
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C
[Cr(H2O)6]3+<[Cr(NH3)6]3+<[Cr(NO2)6]3
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D
[Cr(NH3)6]3+<[Cr(NO2)6]3<[Cr(H2O)6]3+
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Solution

The correct option is C [Cr(H2O)6]3+<[Cr(NH3)6]3+<[Cr(NO2)6]3
For the same cation, stronger the ligand, higher the Δ0.
According to spectrochemical series, ligand strength is in order:
H2O<NH3<NO2
Hence, Δ0 order:
[Cr(H2O)6]3+<[Cr(NH3)6]3+<[Cr(NO2)6]3

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