Question

Indium antimonide has a band gap of 0.23 eV between the valence and the conduction band. Find the temperature at which kT equals the band gap.

Answer 1

Given $E=0.23eV,$

$K=1.38\times {10}^{-23}$

$\because KT=E$

$\Rightarrow 1.38\times {10}^{-23}\times T=0.23\times 1.6\times {10}^{-19}$

$T=\frac{0.23\times 1.6\times {10}^{-19}}{1.38\times {10}^{-23}}$

$=\frac{0.23\times 1.6\times {10}^4}{1.38}$

$=0.2676\times {10}^4$

$=0.267\times {10}^4=2670$