Inequality $a + i b > c + i d$ can be explained only when :

b = 0, c = 0

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b = 0, d = 0

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a = 0, c = 0

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a = 0, d = 0

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Solution

The correct option is A $b = 0, d = 0$
$\begin{matrix} a + i b > c + i d i s v a l i d o n l y w h e n b = 0 & d = 0 a s i n e q u a l i t y i n c o m p l e x n o . i s n o t d e f i n e d . \end{matrix}$

Suggest Corrections

Similar questions

a + ib > c + id can be explained only when

z_{1} = a + i b

z_{2} = c + i d

z_{1} > z_{2}

a + b > 0

c + d > 0

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